A bag contains 2 green, 9 brown, 7 yellow, and 4 blue marbles.

Once a marble is selected, it is not replaced.

Find each probability.

3. P(yellow, then yellow)

Oa 1/11

Ob 2/13

1/6

3/14

Step-by-step explanation:

Given data

2 green,

9 brown,

7 yellow, and

4 blue marbles.

Sample space S = 2+9+7+4= 22

The probability of picking a ball without replacement

Probability of picking each ball

Pr(green) = 2/22= 1/11

Pr(brown ) = 9/21

Pr(yellow) = 7/20

Pr(blue) = 4/19

Probability of picking yellow then another yellow

P(yellow, then yellow)

=(7/22)*(6/21)= 42/462

=1/11

A. 1/11

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0