For the function y=0.5⋅6x, as x approaches negative infinity, what do the y-values approach?

-∞

As x approaches -∞, y=f(x) approaches -∞

Step-by-step explanation:

Given the function;

y = 0.5*6x

We want to determine the limit of y as x tends to minus infinity.

lim x→-∞ f(x) = lim x→-∞ y

y = f(x)

lim x→-∞ f(x) = 0.5*6(-∞)

lim x→-∞ f(x) = 3(-∞)

lim x→-∞ f(x) = -3∞ = -∞

As x tends to -∞, y=f(x) approach -3∞

But, three times minus infinity is still equal to minus infinity.

-3∞ = -∞

Therefore, As x approaches -∞, y=f(x) approach -∞

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

i'm sorry i don't know

step-by-step explanation: