Stacy uses a spinner with six equal sections numbered 2, 2, 3, 4, 5, and 6 to play a game. Stacy spins the pointer 120 times and records the results. The pointer lands 30 times on a section numbered 2, 19 times on 3, 25 times on 4, 29 times on 5, and 17 times on 6. How does the theoretical probability compare with the experimental probability of landing on an even number? Use the drop-down menus to explain your answer.

The probability is greater than the probability of landing on an even number. The probability is 72120 and the probability is 80120.

Even numbers are 2,4,6 for this case and the experimental probability of being even is given by:

Now we can find the theorical probability since we have 6 possible outcomes 2, 2, 3, 4, 5, and 6 we have 4 even numbers in the sample space and the theorical probability is given by:

Then we can conclude that the empirical probability is lower than the theorical probability (0.6<0.667)  for this experiment

Step-by-step explanation:

For this case we wan find the probability associated to the experiment we know that. The pointer lands 30 times on a section numbered 2, 19 times on 3, 25 times on 4, 29 times on 5, and 17 times on 6.

Even numbers are 2,4,6 for this case and the experimental probability of being even is given by:

Now we can find the theorical probability since we have 6 possible outcomes 2, 2, 3, 4, 5, and 6 we have 4 even numbers in the sample space and the theorical probability is given by:

Then we can conclude that the empirical probability is lower than the theorical probability (0.6<0.667)  for this experiment

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints