Mr. and Mrs. Doran have a genetic history such that the probability that a child being born to them with a certain trait is 85%. If they have four children, what is the probability that exactly one of their four children will have that trait? Round your answer to the nearest thousandth.

the probability that exactly one of their four children will have that trait is 0.287%

Step-by-step explanation:

Given;

The probability that a child born to them have a particular trait is

P = 85% = 0.85

The probability that a child born to them will not have a particular trait is

P' = 1 - P = 1-0.85 = 0.15

The probability that exactly one of four children have the trait is:

P(1) = P × P' × P' × P'

P(1) = 0.85 × 0.15 × 0.15 × 0.15

P(1) = 0.00286875

P(1) = 0.287 %

the probability that exactly one of their four children will have that trait is 0.287%

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

answer: it's d

step-by-step explanation: