Maricopa's Success scholarship fund receives a gift of $ 150000. The money is invested in stocks, bonds, and CDs. CDs pay 6 % interest, bonds pay 2.2 % interest, and stocks pay 11.7 % interest. Maricopa Success invests $ 15000 more in bonds than in CDs. If the annual income from the investments is $ 10805 , how much was invested in each account?

Maricopa Success invested in stocks.

Maricopa Success invested in bonds.

Maricopa Success invested in CDs.

$65,000 , $50,000 and $35,000

Step-by-step explanation:

Lets us assume the CDs be C, stocks be S and Bonds be B

Given that

Total scholarship fund received = $150,000

i.e

C + S + B = $150,000 (1)

Now the each items invested percentage is given

And, the annual income from investment is $10,805

So, the next equation is

0.06C + 0.022B + 0.117S = $10,805 (2)

And, it is mentioned that

The $15,000 more in bonds than in CDs

B = C + $15,000 (3)

Now put the equation 3 in equation C is

2C + S = $135,000   (4)

0.082C + 0.117S = $10,475 (5)

Now multiply the 0.117S in equation 4

So

0.234C + 0.117S = $15,795

0.082C + 0.117S = $10,475

After solving this

0.152C = $5,320

C = CDS = $35,000

So

B = $35,000 + $15,000

B=   Bonds = $50,000

And S = Stock = $65,000

its a, i had the same answer, its from study island right

step-by-step explanation:

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !