Una avioneta despega con un ángulo de elevación de 12° respecto al suelo si ha recorrido 48 metros en la misma dirección ¿a que altura respecto al suelo se encuentra la avioneta en ese momento

9.98 meters

Step-by-step explanation:

Angle = 12°

Displacement = 48 m

The height, or displacement in the y-axis will be equal to the opposite cathetus of a triangle rectangle where the hypotenuse is the displacement, then we can find that the displacement in the y-axis is:

h = sin(12°)*48m = 9.98m

answer: the first one

step-by-step explanation: use a calculator and divide the minutes by the dollars.

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i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

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