Which of these pairs of functions are inverse functions?
fix) = 25–1+1 and g(?)=log, (7-1)-1
$1.x) = }(in (1) –1) and g(n) = 2e25+1
f(x) = 41n(52) and g(5)=2***
fix)=109–10–10 and g(x)=logzo(+10)–10

is should be y = 5x

step-by-step explanation:

correct me if im wrong

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.