Solve the following system.
1
v=()x2 + 2*
2 + 2x-1 and 3x-y=1

x = 1 + i, x = 1 - i

Step-by-step explanation:

Make the second equation y = 3x - 1

Substitute: 3x - 1 = 1/2x^2 + 2x

Simplify: 6x - 2 = x^2 + 4x

x^2 + 4x + 2 = 6x

x^2 - 2x + 2 = 0

Complete the square: x^2 - 2x + 1 = - 1

(x - 1)^2 = -1

x - 1 = ± √-1

Take out the negative: x - 1 = ± i

x = 1 + i, x = 1 - i

i is for imaginary number

(0,-1) and (2,5) for the answers.

Step-by-step explanation:

Can someone please answer my question from my profile please thank you

(3x-8) or (3x+8)

step-by-step explanation: