Find the 64th term of the following arithmetic sequence.

17, 26, 35, 44, ...

take the difference

26-17=9

35-26=9

the first term is 17

and the nth term is 64

use the formula

tn=a+(n-1) d

let a be 17

let n be 64

let d be 9

then you substitute

t64=17+(64-1)9

=17+(63)9

=17+567

=584

so the 64th term is 584.

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

it is c, trust i got your back lol

step-by-step explanation: