Reflect ΔECD over segment AC. This establishes that . Then, translate point E' to point A. This establishes that . Therefore, ΔACB ~ ΔECD by the AA similarity postulate.
a. ∠ABC ≅ ∠E'D'C'; ∠E'D'C' ≅ ∠ABC
b. ∠ACB ≅ ∠E'C'D'; ∠D'E'C' ≅ ∠BAC
c. ∠ACB ≅ ∠E'C'D'; ∠E'D'C' ≅ ∠ABC
d. ∠ABC ≅ ∠E'D'C'; ∠D'E'C' ≅ ∠BAC

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

the diver is 33 feet below the surface.

step-by-step explanation:

hope this

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