What is the distance from the right center field fence to third base? Show all of your work and round
your answer to the nearest tenth of a foot

Step-by-step explanation:

Given:  Figure

To find: distance from the right center field fence to third base

Solution:

In a right angled triangle,

using Pythagoras theorem, square of hypotenuse is equal to sum of squares of base and perpendicular.

In ΔBAC,

So,

distance from the right center field fence to third base is 381.5 foot.

is should be y = 5x

step-by-step explanation:

correct me if im wrong

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)