What is the remainder when x^3 - 1 is divided by (x+2)

The remainder is 9

Step-by-step explanation:

Mikey, I'm going to find the answer to this problem using synthetic division.

x^3 - 1 needs to be written as 1x^3 + 0x2 - 0x - 1.  Thus, the coefficients for x^3 - 1 are {1, 0, 0, -1}.

Division of x^3 - 1 by x + 2 requires that we use -2 as a possible root/solution.  Setting up synthetic division, we get:

-2   /    1    0    0     -1

                -2    4    -8

          1      -2    4    -9      The remainder is 9.

answer is 67%

step-by-step explanation:

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i