What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)?
-8
-4
33
49

49

Step-by-step explanation:

f(x)=-(x-3)(x+11)

The zeros of the equation are 3 and -11

The vertex is  1/2 way between the two values

(3+-11)/2 = -8/2 = -4

The vertex is at x= -4

We substitute this value into the equation to find the y value

f(x)=-(-4-3)(-4+11)

    = -(-7)(7)

    =49

49 just took the unit review

Step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3