Oints
A survey asks teachers and students whether they would like the new school
mascot to be a pirate or a moose. This table shows the results.
Pirates
Moose
Total
Students
75
15
90
Teachers
5
15
20
Total
80
30
110
A person is randomly selected from those surveyed.
Are being a student and preferring "pirate" independent events? Why or why
not?
O A. No, they are not independent because P(student) = 0.82 and
P(student|pirate) = 0.94.
O B. Yes, they are independent because P(student) = 0.82 and
P(student pirate) *0.941hy
C. No, they are not independent because P(student) - 0.82 and
P(student pirate) - 0.83.
O D. Yes, they are independent because P(student) - 0.82 and
P(student pirate) - 0.83.

48 / 6 = x

in this case, x will equal the amount of money in each card!

x therefore will be 8.

trent had $8 in each birthday card.

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.