When using the quadratic formula we call the part under that radical the discriminant this part of the formula can be used to help us determine the types of solutions a quadratic equation has before we solve it check all of the statements that apply.
A. if the discriminant is zero there is real solution
B. if the discriminant is negative there are 0 real solutions
C. if the discriminant is positive there are 2 real solutions

A, B, and C

Step-by-step explanation:

The discriminant is denoted by b^2 - 4ac, and it can give us information about the roots of the quadratic equation.

It tells us that if:

- b^2 - 4ac < 0 , then there are 0 real solutions; they're all imaginary (involving the letter i, which is the square root of -1)

- b^2 - 4ac = 0 , then there is 1 real solution; this 1 solution has a multiplicity of 2 because the roots of the quadratic are the same number

- b^2 - 4ac > 0 , then there are 2 real solutions; there are no imaginary solutions

Looking at the possible choices, we see that all of A (A, I'm assuming you meant to write "if the discriminant is zero there is one real solution"), B, and C reflect the above properties.

Thus, they're all right.

A. if the discriminant is zero there is real solution

B. if the discriminant is negative there are 0 real solutions

C. if the discriminant is positive there are 2 real solutions

Step-by-step explanation:

B² - 4AC is the discriminant

If B²-4AC < 0, no real roots

If B2-4AC = 0, roots are real and repeated

If B²-4AC > 0, roots are real and distinct

5x+10 is the correct one

hope this

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic