Question 11
BD is an angle bisector at ZABC and MZABC = 122° and MZABD = 8z - 3 solve for x
A
X=8
B
X=61
С
X=15.625
D
X=7.625

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group