Mr. And Ms. Wakani have a number of children. If 0.625 of the family are female, find the smallest number of children that could be in the Wakani family.

The smallest number of children that could be in the Wakani family is 5.

Step-by-step explanation:

The number of children(both male and female) is a discrete number. That is, it is a countable number, 1,2,3,...

We solve this by trial an error.

1 children:

0.625*1 = 0.625 female. Not possible.

2 children:

0.625*2 = 1.25 female. Not possible

3 children:

0.625*3 = 1.875 female. Not possible

4 children:

0.625*4 = 2.5 female. Not possible

5 children:

0.625*5 = 3.125 female. Not possible.

6 children:

0.625*6 = 3.75 female. Not possible

7 children:

0.625*7 = 4.375 female. Not possible

8 children:

0.625*8 = 5 female. Possible

The smallest number of children that could be in the Wakani family is 5.

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

7

step-by-step explanation:

i'm assuming you need to figure out how many campers go into each tent.

i got the answer by:

24+4=28

28/4=7