Kevin started his science test at 2{:}34\text { p. M.}2:34 p. M.2, colon, 34, start text, space, p, point, m, point, end text and finished the test 757575 minutes later. Kevin has football practice at 4{:}15 \text{ p. M.}4:15 p. M.4, colon, 15, start text, space, p, point, m, point, end text How much time did Kevin have between the end of the test and the beginning of football practice?

26 Minutes.

Step-by-step explanation:

Kevin started his science test at

He finished the test 75 minutes later.

Now: 75 Minutes = 1 hr 15 Minutes

2:34 + 75 Minutes

=2:34+1:15

=3:49 P.M.

Kevin finished his test by 3:49 P.M.

Kevin has football practice at 4:15 P.M.

Therefore, the time Kevin had between the end of the test and the beginning of football practice

=4:15 P.M.-3:49 P.M.

=26 Minutes.

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet