Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of z0 = 5i.
a.
3 + 8i, 9 - 14i, 21 - 26i
c.
3 + 8i, 9 + 14i, 21 + 26i
b.
3 + 8i, 11 - 16i, 23 - 28i
d.
3 + 8i, 11 + 16i, 23 + 28i

Please select the best answer from the choices provided

A
B
C
D

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

i dont know

step-by-step explanation: