For parallelogram ABCD, what is the perimeter and measure of AC?

Perimeter = 68 Units

AC = 30 Units

Step-by-step explanation:

The diagonals AC and BD of parallelogram ABCD are bisecting each other by making 90° angle, this tells us that it is a RHOMBUS.

All sides of rhombus are congruent.

AB = 17 units....(given)

Therefore,

Perimeter = 4*17 = 68 Units

Let diagonals AC and BD intersects at point O.

Therefore, by Pythagoras theorem:

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b