A plane is flying at an elevation of 25000feet. It is within the sight of the airport and the pilot finds that the angle of depression to the airport is 14 degrees. Find the diagonal distance between the plane and the base of the airport.

The distance between the plane and the base of the airport = 103339.14 ft

Step-by-step explanation:

Consider the diagram attached.

We can notice that the a triangle (ABC) can be formed between the plane, the airport, and a vertical line drawn from the ground to the plane showing its altitude.

The angle of depression is 14 degrees. This means that angle BAC is 90 - 14 = 76 degrees.

From triangle laws, we will have that

Hence, the distance between the plane and the base of the airport = 103339.14 ft

what's that

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²