Among Drivers insured by a company, 60% are woman, 35% are at high-risk and 22% are high-risk women. The probability that the driver is either high-risk or a woman is?

The probability of a driver being high-risk or a woman is 73%.

Step-by-step explanation:

The probability of a driver is either high-risk or a woman is given by the probability of the driver being high-ris added by the probability of it being a woman subtractad by the probability of it being high-risk and a woman:

p(high-risk or woman) = p(high-risk) + p(woman) - p(high-risk and woman)

p(high-risk or woman) = 35% + 60% - 22%

p(high-risk or woman) = 73%

The probability of a driver being high-risk or a woman is 73%.

answer: check all that apply, where the options?

step-by-step explanation:

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.