The two-way frequency table below shows data on a student's performance on a math test and that student's
gender for students in Ms. Matchenbacker's class.
Complete the following two-way table of row relative frequencies.
(If necessary, round your answers to the nearest hundredth.)

"female" and "pass" = 0.7368

"female" and "fail" = 0.2632

"male" and "pass" = 0..7368

"male" and "fail" = 0.2632

Step-by-step explanation:

To find the values for the row relative frequency, we just need to divide each value of the first table by the sum of the values of its respective row.

So, we will have that:

Relative value for "female" and "pass": 42 / (42 + 15) = 0.7368

Relative value for "female" and "fail": 15 / (42 + 15) = 0.2632

Relative value for "male" and "pass": 14 / (14 + 5) = 0..7368

Relative value for "male" and "fail": 5 / (14 + 5) = 0.2632

two data sets with the same median will not have the same varaibility

step-by-step explanation:

$79500

step-by-step explanation: