Identify the graph that correctly represents the inequality |x + 1| + 2 > 5.

The greater than 3 means that the graph will have a shaded region for when the absolute value of (x+1) is greater than 3.

The absolute value means that we are interested in the magnitude of x+1. That means that the the graph will be shaded where x+1 > 3, and where -x-1 > 3

If we solve both of these for x, we get:

x > 2 and x < -4

So the graph will look like the attached picture. Notice that the vertical lines are dotted rather than solid. This means that we are dealing with a greater than sign, not a greater than or equal to.

brainliest please

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the answer is 62.8 cubic units