Question 5 (20 points) Circle L is shown. Line segments K L and M L are radii. The length of K L is 12. Angle M L K is 60 degrees. Sector M L K with a 60 degree angle is shaded. What is the area of the sector that is not shaded? a 24π square units b 120π square units c 12π square units d 144π square units

b) is correct 120π square units

Step-by-step explanation:

The sector that is not shaded froms a 300 degree angle. The area of that sector and its angle are proportional with the area of the entire circle and its angle, which is 360 degrees.

We start by computing the area of the circle. Since the radius is 12 units, then the area of the circle is 12² * π = 144π square units. Therefore, the area of the non shaded area is

144π * 300/360 = 120π square units

as option b) suggests.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x