Mathematics, 24.05.2020 21:58 shels10tay

Cos(θ)=√2/2, and 3pi/2 < θ < 2pi, evaluate sin(θ) and tan(θ)

sin(θ)=?
A. -√2
B. -√2/2 ⬅
C. √2/2
D. √2
tan(θ)= -1

Answers: 3

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Cos(θ)=√2/2, and 3pi/2 < θ < 2pi, evaluate sin(θ) and tan(θ)

sin(θ)=?
A. -√2

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Cos(θ)=√2/2, and 3pi/2 < θ < 2pi, evaluate sin(θ) and tan(θ)sin(θ)=?A. -√2B. -√2/2 ⬅C. √2/2D. √2tan(θ)= -1

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Another question on Mathematics

Cos(θ)=√2/2, and 3pi/2 < θ < 2pi, evaluate sin(θ) and tan(θ)

sin(θ)=?
A. -√2
B. -√2/2 ⬅
C. √2/2
D. √2
tan(θ)= -1