The graph of the function f(x) =ax2+bc+c is given below. Could the factors of f(x) be (x+2) and (x+4)? Based on the graph, explain why or why not.

 neither can be a factor

Step-by-step explanation:

If (x -a) is a factor, then value of the function will be zero at x=a. Here, the function has a value of zero (x-intercept) at x = -1 and x = 3. Hence (x+1) and (x-3) are factors, but (x+2) and (x+4) are not. The function is non-zero at x=-2 and x=-4.

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.