The triangular roof section of a house is to be painted. It measures 8.8m at the base and is 4.6m high. if one liter of paint covers 4 square meters, how much is needed to give this roof section three coats of paint

Step-by-step explanation:

Since the roof is triangular, we would the amount of paint required by determining the surface area of the roof. We would apply the formula for determining the area of a triangle which is expressed as

Area = 1/2 × base × height

From the information given,

Height = 4.6m

Base = 8.8m

Surface area = 1/2 × 8.8 × 4.6 = 20.24m²

if one liter of paint covers 4 square meters, then the amount of paint needed to cover 20.24m² is

20.24/4 = 5.06 liters

It means that 5.06 litres would be required for one coat of paint. The number of litres required for three coats of paint is

5.06 × 3 = 15.18 litres

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

an altitude of 15,000 feet

step-by-step explanation: