Mathematics, 24.05.2020 23:58 gianna78

The shoes clerks are paid on commiddion if thr clerk receives a 12% commission on total purcase amounts befor taxes is applied how mych would the commission be for isacc purchase with and without a coupon

Answers: 2

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Answer from: leoiscoolcool

1) $84.53

2) $63.40

3) Without the coupon, store clerk's commission = $9.48

With the 25% discount coupon, store clerk's commission = $7.11

Step-by-step explanation:

Complete Question

Isaac is purchasing two pairs of shoes—one pair for $37.00 and the second pair for $42.00. The state sales tax applied to isaac’s bill is 7%.

1) How much is isaac’s total bill? show your work

2) If isaac uses a coupon entitling him to a 25% discount off the purchase price before tax, how much will his bill be? assume that a 7% sales tax is applied to the discounted price.

3) The shoe store’s clerks are paid on commission. If the clerk receives a 12% commission on total purchase amounts before tax is applied, how much would the commission be for isaac’s purchase with and without a coupon?

Total price of the shoes bought by Isaac = $37 + $42 = $79

1) With a sales tax of 7%, how much does Isaac pay?

The total payable amount will now be (1 + 7%) of the price of the shoes bought by Isaac.

That is, 1.07 × 79 = $84.53

2) There's a 25% discount and a 7% sales tax after the discount.

The price of the shoes after the discount would be (1 - 25%) of $79

That is, (1 - 0.25) × 79 = 0.75 × 79 = $59.25

Then, a sales tax of 7% brings the payable amount to (1 + 7%) of $59.25

That is, (1.07 × 59.25) = $63.3975 = $63.40

3) Store clerk's commission = 12% of shoe price before sales tax

Without the coupon, the price of the shoes = $79.

Store clerk's commission = 12% of $79 = 0.12 × 79 = $9.48

With the 25% discount coupon, price of the shoes becomes 0.75 × 79 = $59.25

Store clerk's commission = 12% of $59.25 = 0.12 × 59.25 = $7.11

Hope this Helps!!!

Answer from: Quest

70,000 + 6,000 + 800 + 30

step-by-step explanation:

Answer from: Quest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

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