What is this equation in standard form?

q^2 +5q -36 =0

Step-by-step explanation:

Standard from is

ax^2 + bx+c =0

6 q^2 +3q = 5q^2 -2q +36

Subtract 5q^2 from each side

6 q^2 +3q  -5q^2= 5q^2-5q^2 -2q +36

q^2 +3q =  -2q +36

Add 2q to each side

q^2 +3q+2q = -2q+2q +36

q^2 +5q = 36

Subtract 36 from each side

q^2 +5q -36 =0

q² + 5q - 36 = 0

Step-by-step explanation:

6q² + 3q = 5q² - 2q + 36

6q² - 5q² + 3q + 2q - 36 = 0

q² + 5q - 36 = 0

srry idk

step-by-step explanation:

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .