For which function is the average rate of change over the interval 1 < x < 5 greater than the average rate of change over the same interval for the function g(x) = 1.8x^2?
A.=f(x) = x^2
B.=g(x) = 1.2x^2
C.=h(x) = 1.5x^2
D.=k(x) = 2x^2

D.=k(x) = 2x^2

Step-by-step explanation:

Average rate of change:

Given a function y, the average rate of change S of in an interval   will be given by the following equation:

In this problem, we have that:

Interval (1,5), so

Then

All options are compared to g(x).

g(5) = 1.8*(5)^2 = 45

g(1) = 1.8*(1)^2 = 1.8

Which one has a greater average rate of change?

Whichever has an average rate of change greater than 10.8.

A.=f(x) = x^2

f(5) = 5^2 = 25

f(1) = 1^2 = 1

Smaller than 10.8, so this is not the answer.

B.=g(x) = 1.2x^2

g(5) = 1.2*(5)^2 = 30

g(1) = 1.2*(1)^2 = 1.2

Smaller than 10.8, so this is not the answer.

C.=h(x) = 1.5x^2

h(5) = 1.5*(5)^2 = 37.5

h(1) = 1.5*(1)^2 = 1.5

Smaller than 10.8, so this is not the answer.

D.=k(x) = 2x^2

k(5) = 2*(5)^2 = 50

k(1) = 2*(1)^2 = 2

Greater than 10.8, this is the answer.

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

chicken nugget stir fry

step-by-step explanation: