At the 2012 Summer Olympic Games in London, in the Men's Shot Put qualifying round, the distances ranged from 17.58 meters to 21.36 meters with a mean distance of 19.64 meters and a standard deviation equal to 0.92 meters. If the distribution were truly a normal distribution, what percent of the athletes would have had a distance greater than 20.56 meters, one standard deviation above the mean? There were 40 athletes in the competition. How many athletes does that represent?

a. about 20 athletes
b. about 26 athletes
c. about 6 athletes

One standard deviation above the mean means a z-score of 1.0. If we put this into the calculator as normalcdf(1,999) = .159

15.9 percent of the athletes would have a distance greater than 20.56 meters.

Now multiply the number of athletes by the percent.

.159 * 40 = 6.346 = about 6 athletes

c. about 6 athletes

answer: i would say b

step-by-step explanation:

with the way the question is worded, i believe b is the answer

the cost of the apple depends on the weight

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d