(I will mark brainlest, please help me. I'm just really confused.) (25 POINTS)

A rocket is launched upward from a height of 50 feet off the ground with an initial vertical velocity of 200 feet per second. When does the rocket ship reach a height of 600 feet? The flight of the rocket ship takes a parabolic path from the ground and f(t) models the flight of the ship.

(I attached a photo of the problem below.)

The rocket ship reaches of height of 600 feet at t=8.415

Step-by-step explanation:

First, plug in the values you know. f(t) is equal to 600, the amount of feet at time t. The vertical velocity and initial heights should also be plugged in. You should end up with an equation that looks like:

600 = -16t^2 + 200t +50.

Simply use the quadratic formula to solve for t. You'll get two answers, one negative and one positive. Choose the positive one, as the negative answer is impossible to answer a real life time problem.

The answer is 8.415.

ege

step-by-step explanation:

egge

1/5^2 = 7.56/45