Expand (2x-3y+3)^2

PLEASE HELP!!

4x² + 9y² + 12x - 18y - 12xy + 9

Step-by-step explanation:

Given

(2x - 3y + 3)² = (2x - 3y + 3)(2x - 3y + 3)

Each term in the second factor is multiplied by each term in the first factor, that is

2x(2x - 3y + 3) - 3y(2x - 3y + 3) + 3(2x - 3y + 3)

Distribute the 3 parenthesis

= 4x² - 6xy + 6x - 6xy + 9y² - 9y + 6x - 9y + 9 ← collect like terms

= 4x² + 9y² + 12x - 18y - 12xy + 9

Step-by-step explanation:

(x+ y + z)² = x² +y² + z² + 2xy +2yz + 2zx

Here, x = 2x   ; y = -3y  & z = 3

(2x - 3y + 3)² = (2x)² + (-3y)² + 3² + 2(2x)(-3y) + 2(-3y)3 + 2*3*(2x)

                    = 4x² + 9y² + 9  - 12xy - 18y + 12x

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x