Use synthetic division to solve (3x4+6x3+2x2+9x+10)+(x+2). What is the quotient?
3x3+ 12x² + 26x+61 +
132/X+ 2 3x4+2x2 + 5x

The quotient is .

Step-by-step explanation:

The dividend is

The coefficient of dividend are 3,6,2,9 and the constant term is 10.

The divisor is (x+2), then divisor in the for of (x-c), therefore the value of c is -2.

Write -2 and the coefficient in the top row.

Now write first coefficient as it is in bottom row.

Multiply -2 and 3 are write the result in middle row. Then add 6 and -6.

Apply same process as shown below.

The bottom row show the coefficient and the last term of the bottom row represents the remainder.

The degree of the quotient is one less than the degree of the polynomial. Therefore the degree of quotient is 3. The quotient is

The remainder is 0.

Step-by-step explanation:

(3x^4+6x^3+2x^2+9x+10)+(x+2)

Remover parentheses:

3x^4+6x^3+2x^2+9x+10+x+2

Group like terms:

3x^4+6x^3+2x^2+9x+x+10+2

Add similar elements:

9x+x= 10x

3x^4+6x^3+2x^2+10x+10+2

Add the numbers:

10+2= 12

3x^4+6x^3+2x^2+10x+12

Your Answer Is 3x^4+6x^3+2x^2+10x+12

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x+14

step-by-step explanation:

where are the images of the functions i can only see the question you typed.

step-by-step explanation: