Once you have a single variable isolated in one of the two equations in a system, the second step of using substitution
to solve the system of equations is to
A. solve for the second variable in the other equation
B. solve for the second variable in the same equation
C. substitute the expression equal to the solved variable into the other equation
D. substitute the expression equal to the solved variable into its original equation
Please select the best answer from the choices provided
ОА
О В
D
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C. substitute the expression equal to the solved variable into the other equation

Step-by-step explanation:

In a system of equations for any method, for this example I'll use subtraction, first, you isolate the variable in the equation. In your question this is already done and it is asking for the next step. Second, you substitute the value of the found variable into the second equation and simplify for the other variable. Then, last, these terms can be substituted back into either equation to check.  

For example,

x + y = 4, 2x - 3y = 3 isolate x in the first equation

x = 4 - y substitute this into the second equation

2(4 - y) - 3y = 3 simplify

-5y = -5, or y = 1 substitute this into the second equation

x + 1 = 4 or x = 3

Solved this is (3,1)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

∡ eia and ∡ kij are congruent

step-by-step explanation: