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Jocelyn has x dimes and y quarters. She has a minimum of 16 coins worth no more
than $3 combined. Solve this system of inequalities graphically and determine one
possible solution.

20 dimes and 2  quarters

Step-by-step explanation:

x = number of dimes

y  = number of quarters

minimum is greater than or equal to ≥

x+y ≥16

no more than is less than or equal to ≤ ,

value of dime is $ 0.10

value of quarter is $0.25 so

0.10x + 0.25y ≤ 3.00

Rewrite inequalities in terms of y:

y ≥16 - x

(0.25/0.25)y ≤ (3.00/0.25)-(0.10/0.25)x→

y≤12 - 0.4x

Graph system: see file