What is the student error in the multiplication below?

Multiply the ones: 957 times 23 = 2871. Above the 9 in 957 is 1, above the 5 in 957 is 2.

Multiply the tens: 957 times 23 = 2871. 2871 + 1914 = blank. Above the 9 in 957 is 1, above the 5 in 957 is 1.

When multiplying the ones, the student did not carry over a ten to the next place in the first multiplication.

When multiplying the ones, the student should have calculated 3 times 2 plus 5 as 11 and placed a 1 in the tens place.

When multiplying the tens, the student did not use the 0 place holder for the ones place.

When multiplying the tens, the student should have calculated 2 times 1 plus 9 as 11 and used a 1 should in the hundreds place.

Question:

Options

1) When multiplying the ones, the student did not carry over a ten to the next place in the first multiplication.

2) When multiplying the ones, the student should have calculated 3 times 2 plus 5 as 11 and placed a 1 in the tens place.

3) When multiplying the tens, the student did not use the 0 place holder for the ones place.

4) When multiplying the tens, the student should have calculated 2 times 1 plus 9 as 11 and used a 1 should in the hundreds place.

The correct option is;

4) When multiplying the tens, the student did not use the 0 place holder for the ones place

Step-by-step explanation:

Here we have when doing long multiplication, the student correctly multiplies the ones as 2871, however, before commencing multiplication of the tens, a 0 should be placed in the ones place of the result as a place holder such that the outcome of the multiplication of the tens should be;

19140

Hence, the correct result should be 2871 + 19140 = 22011

The correct option is therefore, that "When multiplying the tens, the student did not use the 0 place holder for the ones place."

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

d

step-by-step explanation: