A fair dice is rolled 3 times in a row. The outcomes are shown below.

Calculate the probability of all three events occurring.

Roll Outcome
1st 6
2nd factor of 12
3rd less than 6

25/216

Step-by-step explanation:

P( 6) = number of 6's / total number of outcomes

        =1/6

Then roll again

factor of 12: 1,2,3,4,6,12 =

1,2,3,4,6 are possible rolls = 5

P ( factor of 12)=number of numbers that are factor of 12 / total number of outcomes        = 5/6

Then roll again

P( number less than 6) = numbers less than 6 / total

                                      =5/6

P (6, factors of 12, number less than 6) = 1/6*5/6 *5/6

                                                                 =25/216

i believe the correct answer is b.