The equation for a circle is (x-2)2+(y+3)2=9, what is the center of the circle?

(2, -3)

Step-by-step explanation:

Compare the given  (x-2)2+(y+3)2=9 to the standard equation

                                 (x - h)^2 + (y - k)^2 = r^2.

It becomes obvious that h = 2, k = -3 and r = 3.

The center of this circle is (h, k):  (2, -3).

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21