Which shows the correct substitution of the values a, b, and from the equation 0 =-3x - 2x + 6 into the quadratic
formula?
Quadratic formula: x= -1702-400
20
x=-(-2) IV(-2)2-4(-3)(6)
21-3)
-21/22-41-3)(6
2(-3)
-(-2) 1V(-2)2 - 4(3)(6)
2(3)
-2 1722 - 4(3)0
2(3)

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step-by-step explanation:

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step-by-step explanation:

answer

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0