An envelope is 6 in wide and has a diagonal of 11 in. How long is the envelope QUICK

9.22 in

Step-by-step explanation:

Use the pythagorean theorem, because this is a right triangle.

a^2 + b^2 = c^2

6^2 + b^2 = 11^2

36 + b^2 = 11^2

b^2 = 85

b = 9.22 in

b =9.219544457 inches

Step-by-step explanation:

We can use the Pythagorean theorem

a^2+b^2 = c^2

Where one of the legs is 6 and the hypotenuse is 11

6^2 + b^2 = 11^2

36+ b^2 = 121

Subtract 36 from each side

b^2 = 121-36

b^2=85

Take the square root of each side

sqrt(b^2) = sqrt(85)

b =9.219544457

idk

step-by-step explanation:

maybe try   if it is work from a book, if not try