2x + y 2 =6
3x-2y2 = -5

  (x, y) = (1, ±2)

Step-by-step explanation:

To solve this pair of equations, one can add the second equation to twice the first:

  2(2x +y^2) +(3x -2y^2) = 2(6) +(-5)

  4x +3x = 12 -5 . . . . simplify a bit

  7x = 7 . . . . . . . . . . . collect terms

  x = 1  . . . . . . . . . . . . divide by 7

Then y can be found from the first equation:

  y^2 = 6 -2x = 6 -2(1) = 4

  y = ±√4 = ±2

The solutions are ...

  (x, y) = (1, -2)   or   (1, 2)

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

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step-by-step explanation:

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