PLEASE HELP!
What is the equation of the following line written in general form?
points on the graph are (1,6)(6,2)

4x - 5y - 34 = 0

4x - 5y + 34 = 0

4x + 5y - 34 = 0

4x+5y-34=0

Step-by-step explanation:

The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.

My goal is to put in in this form first.  Then I will aim to put it in general form, ax+by+c=0.

So let's give it a go:

m is the change of y over the change of x.

To compute this I'm going to line my points up and subtract vertically, then put 2nd difference over 1st difference.  Like this:

( 1 , 6)

-(6 , 2)

-5   4

So the slope is 4/-5 or -4/5.

So m=-4/5.

Now we are going to find b given y=mx+b and m=-4/5 and we have a point (x,y)=(1,6) [didn't matter what point you chose here].

6=-4/5 (1)+b

6=-4/5    +b

Add 4/5 on both sides:

6+4/5=b

30/5+4/5=b

34/5=b

So the y-intercept is 34/5.

The equation in slope-intercept form is:

y=-4/5 x + 34/5.

In general form, it is sometimes the goal to make all of your coefficients integers so let's do that.  To get rid of the fractions, I'm going to multiply both sides by 5.  This clears the 5's that were on bottom since 5/5=1.

5y=-4x+34

Now add 4x on both sides:

4x+5y=34   This is standard form.

Subtract 34 on both sides:

4x+5y-34=0

do you have the measurements?

r and t.

both are 64 degrees.