A floor has six sections. The total weight supported by the floor at present is 120 pounds.
If the maximum weight that can be supported by the floor is 900 pounds, what is the maximum additional weight that each section of the floor can support. Give the correct answer and the correct equation required for solution.

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation:

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116