Consider this system of equations. Which shows the first equation written in slope-intercept form?
2 (2y+10) = 7*
y=8
y = 7x-10
7
y=zx-5
y = 7x-5
o y = 1 x - 5

Question:

Consider this system of equations. Which shows the first equation written in slope-intercept form?

½(2y + 10) = 7x.

y = 8.

A. y = 7x - 10

B. y = 7x/2 - 5

C. y = 7x - 5

D. y = 7x/4 - 5

C. y = 7x - 5

Step-by-step explanation:

Given

½(2y + 10) = 7x.

Required

Convert to slope intercept form.

To do this, we simply make y the subject of formula from the given equation

We start by writing out the equation

½(2y + 10) = 7x.

Then, we open the bracket

½ * 2y + ½ * 10 = 7x

2y/2 + 10/2 = 7x

y + 5 = 7x

Then, subtract 5 from both sides of the equation

y + 5 - 5 = 7x - 5

y = 7x - 5

The equation can't be simplified any further. So, we've arrived at a solution

Hence, the slope intercept form of ½(2y + 10) = 7x is y = 7x - 5

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

answer: there are 453.592 grams in a pound.