Suppose a normal distribution has a mean of 48 and a standard deviation of 2. what is the probability that a data value is between 44 and 47? round your answer to the nearest tenth of a percent. A. 30.5% B. 31.6% C. 28.6% D. 29.6%

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b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation:

$119.20

step-by-step explanation:

$372.50 - 60% off is $149. $149-20% off is $119.20

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10

your answer is c. 97 (don't delete this again)

step-by-step explanation: