Harrison began a proof.
Given: CE DF
CE= DF because segment CE segment DF.
CD + DE = CE and DE + EF = DF, by the segment addition postulate.
DE + EF = CE by substituting CE for DF.
OD
Prove: CD EF
What is a possible next step in Harrison's proof?

Consider the functions below. function 1 function 2 function 3 select the statement which is true about the functions over the interval [1, 2] a b function 3 has the highest average rate of change function 2 and function 3 have the same average rate of change. function and function 3 have the same average rate of change function 2 has the lowest average rate of change d.