In a sample of 330 randomly selected PCC students it was found that 175 of them have a car. Assume this sample comes from a population that is normally distributed. a. Calculate the EBP then construct a 95% confidence interval estimate of the percentage of PCC students have a car (round the values of the interval to three decimal places). b. Based on your confidence interval, can we conclude that most students at PCC own a car?

a)

And if we convert this interval into % we got (47.615%, 58.385%)

b) For this case since the lower value for the confidence interval is a value lower than 0.5 (50%) we don't have enough evidence to conclude at 10% of significance than  most students at PCC own a car

Step-by-step explanation:

We can begin calculating the best estimator for the true proportion of students at PCC who own a car:

Part a

The confidence level is 95% , and the significance level would be given by and . And the critical values would be given by:

The confidence interval for the true proportion is given by the following formula:  

Replacing the info given we got:

And if we convert this interval into % we got (47.615%, 58.385%)

Part b

For this case since the lower value for the confidence interval is a value lower than 0.5 (50%) we don't have enough evidence to conclude at 10% of significance than  most students at PCC own a car

true

step-by-step explanation:

answer is : muchas/tipicas

have a nice day!

~recklesschicken