One number is 16 more than another number. The two numbers have a sum of 120. Which system of equations could you use to find the two numbers?

y = x-16

y = -x+ 120

Step-by-step explanation:

Let one number be x

let other number be y .

It is given that other number is 16 more than other number.

Let x be the greater number then

Then x will be 16 more than y.

Mathematical equation for this will be

x = y+16

subtracting 16 from both sides

x-16 = y+16 -16

=> x-16 = y

Thus first equation is y = x-16.

It is given that sum of both number is 120.

Thus, sum of x and y is 120

Mathematical equation for this will be

x+y = 120

y = 120 -x  

rearranging x and 120 we have

y = -x +120

Thus, second equation is y = -x+ 120.

system of required equation is

y = x-16

y = -x+ 120

step-by-step explanation:

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation: